What are the solutions to the equation x^2+6x-1=0 ?

The solutions to the equation x^2+6x-1=0 are x=-3+sqrt(10),x=-3-sqrt(10)

Find the zeros of x^2+6x-1=0

The zeros of x^2+6x-1=0 are x=-3+sqrt(10),x=-3-sqrt(10)

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x^{2} + 6 x - 1 = 0

x = - 3 + 10, x = - 3 - 10

Solution steps

x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 1) = 210

x_{1, 2} = \frac{- 6 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 10}{2 \cdot 1}

x = \frac{- 6 + 2 10}{2 \cdot 1} : - 3 + 10

x = \frac{- 6 - 2 10}{2 \cdot 1} : - 3 - 10

The solutions to the quadratic equation are:

x = - 3 + 10, x = - 3 - 10

29 = \frac{b}{- 4} + 15

2 x + 9 + 3 x + x = 5 x + 8

2 (5 v + 3) - 4 (7 v + 1) = - 88

\frac{3}{- 4} g < 18

27 x^{2} - 39 x - 10

What are the solutions to the equation x^2+6x-1=0 ?
The solutions to the equation x^2+6x-1=0 are x=-3+sqrt(10),x=-3-sqrt(10)
Find the zeros of x^2+6x-1=0
The zeros of x^2+6x-1=0 are x=-3+sqrt(10),x=-3-sqrt(10)