What is the d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) ?

The d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) is x(-sin(2t)*2+cos(2t)*2+1/5 e^t)

What is the first d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) ?

The first d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) is x(-sin(2t)*2+cos(2t)*2+1/5 e^t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((x) (cos (2 t) + sin (2 t) + \frac{1}{5} e^{t}))

x (- sin (2 t) \cdot 2 + cos (2 t) \cdot 2 + \frac{1}{5} e^{t})

Solution steps

\frac{d}{d t} ((x) (cos (2 t) + sin (2 t) + \frac{1}{5} e^{t}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d t} (cos (2 t) + sin (2 t) + \frac{1}{5} e^{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d t} (cos (2 t)) + \frac{d}{d t} (sin (2 t)) + \frac{d}{d t} (\frac{1}{5} e^{t}))

\frac{d}{d t} (cos (2 t)) = - sin (2 t) \cdot 2

\frac{d}{d t} (sin (2 t)) = cos (2 t) \cdot 2

\frac{d}{d t} (\frac{1}{5} e^{t}) = \frac{1}{5} e^{t}

= x (- sin (2 t) \cdot 2 + cos (2 t) \cdot 2 + \frac{1}{5} e^{t})

(e^{2 t o + 2 a} + e^{- 2 t o - 2 a}) (e^{2 t} + e^{- 2 t})

e^{a t} u (t - 1)

\frac{d}{d z ( w )} ((w (z (w), x (w), y (w))) (x (w) + y (w)))

\frac{( 12 x - 7 ) ( 12 x + 7 )}{16}

1 + (8 x - 4) e^{- 2 x}

What is the d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) ?
The d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) is x(-sin(2t)*2+cos(2t)*2+1/5 e^t)
What is the first d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) ?
The first d/(dt)((x)(cos(2t)+sin(2t)+1/5 e^t)) is x(-sin(2t)*2+cos(2t)*2+1/5 e^t)