What is expand 1/((s-1)(s+2)(s+4)) ?

The solution to expand 1/((s-1)(s+2)(s+4)) is 1/(s^3+5s^2+2s-8)

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expand 1/((s-1)(s+2)(s+4))

expand

\frac{1}{( s - 1 ) ( s + 2 ) ( s + 4 )}

\frac{1}{s ^{3} + 5 s ^{2} + 2 s - 8}

Solution steps

\frac{1}{( s - 1 ) ( s + 2 ) ( s + 4 )}

Expand

(s - 1) (s + 2) (s + 4) : s^{3} + 5 s^{2} + 2 s - 8

= \frac{1}{s ^{3} + 5 s ^{2} + 2 s - 8}

\frac{k ( z + 0.5 )}{( z + 1 ) ( z - 0.5 ) ( z - 1 )}

\frac{s + 2}{( s ^{2} + 4 s + 5 ) ^{2}}

\frac{9 x ^{2} - x ^{4}}{( 3 - x ^{2} ) ^{2}}

x (y^{6} + 1) d x + y^{2} (x^{4} + 1) d y

\frac{x x + 1 + 2 x + 1}{2 ( x + 1 ) ^{2}}

What is expand 1/((s-1)(s+2)(s+4)) ?
The solution to expand 1/((s-1)(s+2)(s+4)) is 1/(s^3+5s^2+2s-8)