What is expand ((4y^6-1)^2)/(16y^6) ?

The solution to expand ((4y^6-1)^2)/(16y^6) is y^6-1/2+1/(16y^6)

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expand ((4y^6-1)^2)/(16y^6)

expand

\frac{( 4 y ^{6} - 1 ) ^{2}}{16 y ^{6}}

y^{6} - \frac{1}{2} + \frac{1}{16 y ^{6}}

Solution steps

\frac{( 4 y ^{6} - 1 ) ^{2}}{16 y ^{6}}

(4 y^{6} - 1)^{2} = 16 y^{12} - 8 y^{6} + 1

= \frac{16 y ^{12} - 8 y ^{6} + 1}{16 y ^{6}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 y ^{12} - 8 y ^{6} + 1}{16 y ^{6}} = \frac{16 y ^{12}}{16 y ^{6}} - \frac{8 y ^{6}}{16 y ^{6}} + \frac{1}{16 y ^{6}}

= \frac{16 y ^{12}}{16 y ^{6}} - \frac{8 y ^{6}}{16 y ^{6}} + \frac{1}{16 y ^{6}}

Cancel

\frac{16 y ^{12}}{16 y ^{6}} : y^{6}

= y^{6} - \frac{8 y ^{6}}{16 y ^{6}} + \frac{1}{16 y ^{6}}

Cancel

\frac{8 y ^{6}}{16 y ^{6}} : \frac{1}{2}

= y^{6} - \frac{1}{2} + \frac{1}{16 y ^{6}}

\frac{x - 3}{( x + 3 ) ( x + 1 )}

2 (π - θ)

\frac{s ^{2} - s + 1}{( s + 1 ) ^{2}}

- \frac{( 6 x ^{2} + 11 x + 7 )}{( x ^{2} + 5 ) ( x + 3 )}

(3 - x - 1) (6 - x + 2)

What is expand ((4y^6-1)^2)/(16y^6) ?
The solution to expand ((4y^6-1)^2)/(16y^6) is y^6-1/2+1/(16y^6)