What is expand (x-4)/((x-2)(x-3)) ?

The solution to expand (x-4)/((x-2)(x-3)) is (x-4)/(x^2-5x+6)

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expand (x-4)/((x-2)(x-3))

expand

\frac{x - 4}{( x - 2 ) ( x - 3 )}

\frac{x - 4}{x ^{2} - 5 x + 6}

Solution steps

\frac{x - 4}{( x - 2 ) ( x - 3 )}

Expand

(x - 2) (x - 3) : x^{2} - 5 x + 6

= \frac{x - 4}{x ^{2} - 5 x + 6}

s^{2} y (s) - sy (0) - y^{'} (0) - 2 (sy (s) - y (0)) + 2 y (s)

L^{5} U (t - 2) - 3 t U (t - 5)

(\frac{1 - x ^{3}}{1 - x})^{8}

\frac{2 x ^{2} - 9 x + 12}{( x - 2 ) ( x - 3 )}

x (1 - x - y)^{2}

What is expand (x-4)/((x-2)(x-3)) ?
The solution to expand (x-4)/((x-2)(x-3)) is (x-4)/(x^2-5x+6)