What is expand (x^5+1)/((x^2-x)(x^4+2x^2+1)) ?

The solution to expand (x^5+1)/((x^2-x)(x^4+2x^2+1)) is (x^5+1)/(x^6+2x^4+x^2-x^5-2x^3-x)

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expand (x^5+1)/((x^2-x)(x^4+2x^2+1))

expand

\frac{x ^{5} + 1}{( x ^{2} - x ) ( x ^{4} + 2 x ^{2} + 1 )}

\frac{x ^{5} + 1}{x ^{6} + 2 x ^{4} + x ^{2} - x ^{5} - 2 x ^{3} - x}

Solution steps

\frac{x ^{5} + 1}{( x ^{2} - x ) ( x ^{4} + 2 x ^{2} + 1 )}

Expand

(x^{2} - x) (x^{4} + 2 x^{2} + 1) : x^{6} + 2 x^{4} + x^{2} - x^{5} - 2 x^{3} - x

= \frac{x ^{5} + 1}{x ^{6} + 2 x ^{4} + x ^{2} - x ^{5} - 2 x ^{3} - x}

2 e^{- x} x - e^{- x} (x^{2} - 1)

y^{''} (x) - 4 x y^{'} (x) + (4 x^{2} - 2) y

\frac{d ^{3}}{d x ^{3}} ((y) (2 x^{2} - \frac{1}{x ^{3}}))

\frac{4 e ^{- 2 s}}{( s - 1 ) ( s + 4 ) ^{2}}

ln (\frac{2 x}{x - 2})

What is expand (x^5+1)/((x^2-x)(x^4+2x^2+1)) ?
The solution to expand (x^5+1)/((x^2-x)(x^4+2x^2+1)) is (x^5+1)/(x^6+2x^4+x^2-x^5-2x^3-x)