What is (2-6i)/(2-3i) ?

The solution to (2-6i)/(2-3i) is 22/13-6/13 i

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simplify (2-6i)/(2-3i)

simplify

\frac{2 - 6 i}{2 - 3 i}

\frac{22}{13} - \frac{6}{13} i

Solution steps

\frac{2 - 6 i}{2 - 3 i}

Multiply by the conjugate

\frac{2 + 3 i}{2 + 3 i}

= \frac{( 2 - 6 i ) ( 2 + 3 i )}{( 2 - 3 i ) ( 2 + 3 i )}

Simplify

\frac{( 2 - 6 i ) ( 2 + 3 i )}{( 2 - 3 i ) ( 2 + 3 i )} : \frac{22 - 6 i}{13}

= \frac{22 - 6 i}{13}

Rewrite in standard complex form:

\frac{22}{13} - \frac{6}{13} i

= \frac{22}{13} - \frac{6}{13} i

2 a^{2} - 4 a + a - 2

\frac{x}{x + 2} - \frac{2}{x - 1} < 0

\frac{6 ^{- 3}}{6 ^{5}}

2 w^{2} - 26 w - 60

f = 30 e^{- 0.093}