What is expand 3/((z+1)(z-2)^2) ?

The solution to expand 3/((z+1)(z-2)^2) is 3/(z^3-3z^2+4)

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expand 3/((z+1)(z-2)^2)

expand

\frac{3}{( z + 1 ) ( z - 2 ) ^{2}}

\frac{3}{z ^{3} - 3 z ^{2} + 4}

Solution steps

\frac{3}{( z + 1 ) ( z - 2 ) ^{2}}

(z - 2)^{2} = z^{2} - 4 z + 4

= \frac{3}{( z + 1 ) ( z ^{2} - 4 z + 4 )}

Expand

(z + 1) (z^{2} - 4 z + 4) : z^{3} - 3 z^{2} + 4

= \frac{3}{z ^{3} - 3 z ^{2} + 4}

\frac{( 0.2 R ^{2} - 8 R + 8 )}{5 R ^{2} ( R - 2 ) ^{2}}

\frac{9 \cdot x + 6}{( x + 3 ) \cdot x \cdot ( x - 4 )}

\frac{3}{( x - 1 ) ( x + 2 )}

\frac{3 x ^{2} - 4 x + 5}{( x - 1 ) ( x ^{2} + 2 x + 1 )}

(x + 1) (x + 1)!

What is expand 3/((z+1)(z-2)^2) ?
The solution to expand 3/((z+1)(z-2)^2) is 3/(z^3-3z^2+4)