What is expand (3x-1)/((x^2-1)^3) ?

The solution to expand (3x-1)/((x^2-1)^3) is (3x-1)/(x^6-3x^4+3x^2-1)

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expand (3x-1)/((x^2-1)^3)

expand

\frac{3 x - 1}{( x ^{2} - 1 ) ^{3}}

\frac{3 x - 1}{x ^{6} - 3 x ^{4} + 3 x ^{2} - 1}

Solution steps

\frac{3 x - 1}{( x ^{2} - 1 ) ^{3}}

(x^{2} - 1)^{3} = x^{6} - 3 x^{4} + 3 x^{2} - 1

= \frac{3 x - 1}{x ^{6} - 3 x ^{4} + 3 x ^{2} - 1}

\frac{16 x y + 2 - x ^{2} y ^{2} - 28}{16 ( x ^{2} y ^{2} - 4 )}

Q (12, - 13)

\frac{1}{( 2 x + 3 ) ^{2}}

(6 - - 25) (6 + - 25)

\frac{( x - 1 ) ^{3}}{( x - 2 ) ^{2}}

What is expand (3x-1)/((x^2-1)^3) ?
The solution to expand (3x-1)/((x^2-1)^3) is (3x-1)/(x^6-3x^4+3x^2-1)