What is expand (2s+3)/((s-1)^3(s^3+1)) ?

The solution to expand (2s+3)/((s-1)^3(s^3+1)) is (2s+3)/(s^6-3s^5+3s^4-3s^2+3s-1)

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expand (2s+3)/((s-1)^3(s^3+1))

expand

\frac{2 s + 3}{( s - 1 ) ^{3} ( s ^{3} + 1 )}

\frac{2 s + 3}{s ^{6} - 3 s ^{5} + 3 s ^{4} - 3 s ^{2} + 3 s - 1}

Solution steps

\frac{2 s + 3}{( s - 1 ) ^{3} ( s ^{3} + 1 )}

(s - 1)^{3} = s^{3} - 3 s^{2} + 3 s - 1

= \frac{2 s + 3}{( s ^{3} - 3 s ^{2} + 3 s - 1 ) ( s ^{3} + 1 )}

Expand

(s^{3} - 3 s^{2} + 3 s - 1) (s^{3} + 1) : s^{6} - 3 s^{5} + 3 s^{4} - 3 s^{2} + 3 s - 1

= \frac{2 s + 3}{s ^{6} - 3 s ^{5} + 3 s ^{4} - 3 s ^{2} + 3 s - 1}

\frac{1}{( a - x ) ( b - x )}

(cos (\frac{θ}{2}) + sin (\frac{θ}{2}) e^{i φ})^{2}

e^{3 x y} \cdot 3 (y + x \frac{d y}{d x})

50 (24 - 23 e^{- \frac{t}{200}})

Z ((n + 1) (- 2)^{n})

What is expand (2s+3)/((s-1)^3(s^3+1)) ?
The solution to expand (2s+3)/((s-1)^3(s^3+1)) is (2s+3)/(s^6-3s^5+3s^4-3s^2+3s-1)