What is expand ((3-x)^2)/9 ?

The solution to expand ((3-x)^2)/9 is (x^2)/9-(2x)/3+1

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expand ((3-x)^2)/9

expand

\frac{( 3 - x ) ^{2}}{9}

\frac{x ^{2}}{9} - \frac{2 x}{3} + 1

Solution steps

\frac{( 3 - x ) ^{2}}{9}

(3 - x)^{2} = 9 - 6 x + x^{2}

= \frac{9 - 6 x + x ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 - 6 x + x ^{2}}{9} = \frac{9}{9} - \frac{6 x}{9} + \frac{x ^{2}}{9}

= \frac{9}{9} - \frac{6 x}{9} + \frac{x ^{2}}{9}

Apply rule

\frac{a}{a} = 1

\frac{9}{9} = 1

= 1 - \frac{6 x}{9} + \frac{x ^{2}}{9}

Cancel

\frac{6 x}{9} : \frac{2 x}{3}

= 1 - \frac{2 x}{3} + \frac{x ^{2}}{9}

Rewrite in standard form

= \frac{x ^{2}}{9} - \frac{2 x}{3} + 1

A (- 2, - 3) B (1, 3)

- \frac{x ( - x + 1 ) ^{3}}{3}

\frac{1}{81} (e^{9 x} \cdot 9 x - e^{9 x})

x y (x + y) z^{^{'}} + y

What is expand ((3-x)^2)/9 ?
The solution to expand ((3-x)^2)/9 is (x^2)/9-(2x)/3+1