What is expand (3pi(-sqrt(3)+2)ρ^2)/4 ?

The solution to expand (3pi(-sqrt(3)+2)ρ^2)/4 is -(3sqrt(3)piρ^2)/4+(3piρ^2)/2

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expand (3pi(-sqrt(3)+2)ρ^2)/4

expand

\frac{3 π ( - 3 + 2 ) ρ ^{2}}{4}

- \frac{3 3 π ρ ^{2}}{4} + \frac{3 π ρ ^{2}}{2}

Solution steps

\frac{3 π ( - 3 + 2 ) ρ ^{2}}{4}

Expand

3 π (- 3 + 2) ρ^{2} : - 33 π ρ^{2} + 6 π ρ^{2}

= \frac{- 3 3 π ρ ^{2} + 6 π ρ ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 3 π ρ ^{2} + 6 π ρ ^{2}}{4} = - \frac{3 3 π ρ ^{2}}{4} + \frac{6 π ρ ^{2}}{4}

= - \frac{3 3 π ρ ^{2}}{4} + \frac{6 π ρ ^{2}}{4}

Cancel

\frac{6 π ρ ^{2}}{4} : \frac{3 π ρ ^{2}}{2}

= - \frac{3 3 π ρ ^{2}}{4} + \frac{3 π ρ ^{2}}{2}

F (- 3, - 2) V (- 3, - 5)

\frac{d ^{4}}{d x ^{4}} ((y) (- x^{4} + 5 x))

\frac{m ^{3} - 1}{( m + 1 ) ( m ^{2} - m + 1 )}

\frac{( 4 x - 15 ) d x}{( x ^{2} - 4 x + 13 )}

\frac{1}{( s + a ) ^{2}}

What is expand (3pi(-sqrt(3)+2)ρ^2)/4 ?
The solution to expand (3pi(-sqrt(3)+2)ρ^2)/4 is -(3sqrt(3)piρ^2)/4+(3piρ^2)/2