What is expand 2t(45cos(3x)+16e^{-4x}-8sin(2x)) ?

The solution to expand 2t(45cos(3x)+16e^{-4x}-8sin(2x)) is 90tcos(3x)+32e^{-4x}t-16tsin(2x)

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expand 2t(45cos(3x)+16e^{-4x}-8sin(2x))

expand

2 t (45 cos (3 x) + 16 e^{- 4 x} - 8 sin (2 x))

90 t cos (3 x) + 32 e^{- 4 x} t - 16 t sin (2 x)

Solution steps

2 t (45 cos (3 x) + 16 e^{- 4 x} - 8 sin (2 x))

Distribute parentheses

= 2 t \cdot 45 cos (3 x) + 2 t \cdot 16 e^{- 4 x} + 2 t (- 8 sin (2 x))

Apply minus-plus rules

+ (- a) = - a

= 2 \cdot 45 t cos (3 x) + 2 \cdot 16 e^{- 4 x} t - 2 \cdot 8 t sin (2 x)

Simplify

2 \cdot 45 t cos (3 x) + 2 \cdot 16 e^{- 4 x} t - 2 \cdot 8 t sin (2 x) : 90 t cos (3 x) + 32 e^{- 4 x} t - 16 t sin (2 x)

= 90 t cos (3 x) + 32 e^{- 4 x} t - 16 t sin (2 x)

\frac{n \cdot ( n - 1 )}{2}

lo g_{2} (x yz)

\frac{x - 2}{( x - 3 ) ^{2} ( x - 8 )}

\frac{2 x + 1}{( x ^{2} + x ) ^{3}}

\frac{2 ( 1 + ln ( x ) )}{x}

What is expand 2t(45cos(3x)+16e^{-4x}-8sin(2x)) ?
The solution to expand 2t(45cos(3x)+16e^{-4x}-8sin(2x)) is 90tcos(3x)+32e^{-4x}t-16tsin(2x)