What is expand (2pi)/(365)(t-80) ?

The solution to expand (2pi)/(365)(t-80) is (2pit)/(365)-(32pi)/(73)

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expand (2pi)/(365)(t-80)

expand

\frac{2 π}{365} (t - 80)

\frac{2 π t}{365} - \frac{32 π}{73}

Solution steps

\frac{2 π}{365} (t - 80)

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{2 π}{365}, b = t, c = 80

= \frac{2 π}{365} t - \frac{2 π}{365} \cdot 80

= \frac{2 π}{365} t - 80 \cdot \frac{2 π}{365}

Simplify

\frac{2 π}{365} t - 80 \cdot \frac{2 π}{365} : \frac{2 π t}{365} - \frac{32 π}{73}

= \frac{2 π t}{365} - \frac{32 π}{73}

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What is expand (2pi)/(365)(t-80) ?
The solution to expand (2pi)/(365)(t-80) is (2pit)/(365)-(32pi)/(73)