What is expand (x(n+1)(n^2+3))/(n(n^2+2n+4)) ?

The solution to expand (x(n+1)(n^2+3))/(n(n^2+2n+4)) is (n^3x+3nx+n^2x+3x)/(n^3+2n^2+4n)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x(n+1)(n^2+3))/(n(n^2+2n+4))

expand

\frac{x ( n + 1 ) ( n ^{2} + 3 )}{n ( n ^{2} + 2 n + 4 )}

\frac{n ^{3} x + 3 n x + n ^{2} x + 3 x}{n ^{3} + 2 n ^{2} + 4 n}

Solution steps

\frac{x ( n + 1 ) ( n ^{2} + 3 )}{n ( n ^{2} + 2 n + 4 )}

Expand

n (n^{2} + 2 n + 4) : n^{3} + 2 n^{2} + 4 n

= \frac{x ( n + 1 ) ( n ^{2} + 3 )}{n ^{3} + 2 n ^{2} + 4 n}

Expand

x (n + 1) (n^{2} + 3) : n^{3} x + 3 n x + n^{2} x + 3 x

= \frac{n ^{3} x + 3 n x + n ^{2} x + 3 x}{n ^{3} + 2 n ^{2} + 4 n}

\frac{1}{3} (11 ln (11) - 11) + C

(e + 4)^{2}

\frac{s + 1}{s ( s + 5 )}

\frac{3 x ^{2} - ( 4 x + 1 ) x + 2}{x - 1}

\frac{5 ( 3 - 3 )}{3}

What is expand (x(n+1)(n^2+3))/(n(n^2+2n+4)) ?
The solution to expand (x(n+1)(n^2+3))/(n(n^2+2n+4)) is (n^3x+3nx+n^2x+3x)/(n^3+2n^2+4n)