What is expand ((n^2-9)^2)/(9n^2) ?

The solution to expand ((n^2-9)^2)/(9n^2) is (n^2)/9-2+9/(n^2)

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expand ((n^2-9)^2)/(9n^2)

expand

\frac{( n ^{2} - 9 ) ^{2}}{9 n ^{2}}

\frac{n ^{2}}{9} - 2 + \frac{9}{n ^{2}}

Solution steps

\frac{( n ^{2} - 9 ) ^{2}}{9 n ^{2}}

(n^{2} - 9)^{2} = n^{4} - 18 n^{2} + 81

= \frac{n ^{4} - 18 n ^{2} + 81}{9 n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{4} - 18 n ^{2} + 81}{9 n ^{2}} = \frac{n ^{4}}{9 n ^{2}} - \frac{18 n ^{2}}{9 n ^{2}} + \frac{81}{9 n ^{2}}

= \frac{n ^{4}}{9 n ^{2}} - \frac{18 n ^{2}}{9 n ^{2}} + \frac{81}{9 n ^{2}}

Cancel

\frac{n ^{4}}{9 n ^{2}} : \frac{n ^{2}}{9}

= \frac{n ^{2}}{9} - \frac{18 n ^{2}}{9 n ^{2}} + \frac{81}{9 n ^{2}}

Cancel

\frac{18 n ^{2}}{9 n ^{2}} : 2

= \frac{n ^{2}}{9} - 2 + \frac{81}{9 n ^{2}}

Divide the numbers:

\frac{81}{9} = 9

= \frac{n ^{2}}{9} - 2 + \frac{9}{n ^{2}}

\frac{2 ( 45 - 2 15 )}{15}

π (e^{2} - 1)

\frac{( x ^{2} + 3 x + 5 ) n + x ^{2} ( x + 3 ) 2 + 3}{x ^{2} + 3 x + 4}

\frac{( w - 20 ) ( 380 - w )}{2}

1 - (\frac{1600}{( s + 4 ) ( s ^{2} + 40 s + 80 )})

What is expand ((n^2-9)^2)/(9n^2) ?
The solution to expand ((n^2-9)^2)/(9n^2) is (n^2)/9-2+9/(n^2)