What is expand ((x^2+4)^2)/(4x) ?

The solution to expand ((x^2+4)^2)/(4x) is (x^3)/4+2x+4/x

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expand ((x^2+4)^2)/(4x)

expand

\frac{( x ^{2} + 4 ) ^{2}}{4 x}

\frac{x ^{3}}{4} + 2 x + \frac{4}{x}

Solution steps

\frac{( x ^{2} + 4 ) ^{2}}{4 x}

(x^{2} + 4)^{2} = x^{4} + 8 x^{2} + 16

= \frac{x ^{4} + 8 x ^{2} + 16}{4 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} + 8 x ^{2} + 16}{4 x} = \frac{x ^{4}}{4 x} + \frac{8 x ^{2}}{4 x} + \frac{16}{4 x}

= \frac{x ^{4}}{4 x} + \frac{8 x ^{2}}{4 x} + \frac{16}{4 x}

Cancel

\frac{x ^{4}}{4 x} : \frac{x ^{3}}{4}

= \frac{x ^{3}}{4} + \frac{8 x ^{2}}{4 x} + \frac{16}{4 x}

Cancel

\frac{8 x ^{2}}{4 x} : 2 x

= \frac{x ^{3}}{4} + 2 x + \frac{16}{4 x}

Divide the numbers:

\frac{16}{4} = 4

= \frac{x ^{3}}{4} + 2 x + \frac{4}{x}

0.54 + \frac{5.72 \cdot ( z - 1 )}{z - 0.0067}

\frac{1}{( p - x ) ( q - x )}

(2, - 3) y (6, - 1)

\frac{1}{z ( z - 8 ) ^{2}}

\frac{3}{( x ^{2} - 9 ) ^{2}}

What is expand ((x^2+4)^2)/(4x) ?
The solution to expand ((x^2+4)^2)/(4x) is (x^3)/4+2x+4/x