What are the solutions to the equation 5x^2-4x-9=-9 ?

The solutions to the equation 5x^2-4x-9=-9 are x= 4/5 ,x=0

Find the zeros of 5x^2-4x-9=-9

The zeros of 5x^2-4x-9=-9 are x= 4/5 ,x=0

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5 x^{2} - 4 x - 9 = - 9

x = \frac{4}{5}, x = 0

Solution steps

5 x^{2} - 4 x - 9 = - 9

Move

9

to the left side

5 x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 5}

x = \frac{- ( - 4 ) + 4}{2 \cdot 5} : \frac{4}{5}

x = \frac{- ( - 4 ) - 4}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = \frac{4}{5}, x = 0

\frac{1}{\frac{2}{5}}

(x + 2)^{2} (x + 8) (x - 6) < 0

\frac{n}{4} - \frac{5 n}{8} = \frac{1}{4}

\frac{x}{5} + 3 = 2

6 x + 7 = 37

What are the solutions to the equation 5x^2-4x-9=-9 ?
The solutions to the equation 5x^2-4x-9=-9 are x= 4/5 ,x=0
Find the zeros of 5x^2-4x-9=-9
The zeros of 5x^2-4x-9=-9 are x= 4/5 ,x=0