What is expand (x-1)y''(x)+y'(x) ?

The solution to expand (x-1)y''(x)+y'(x) is xy''(x)-y''(x)+y'(x)

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expand (x-1)y''(x)+y'(x)

expand

(x - 1) y^{''} (x) + y^{'} (x)

x y'' (x) - y'' (x) + y' (x)

Solution steps

(x - 1) y^{''} (x) + y^{'} (x)

Expand

y^{''} (x) (x - 1) : x y^{''} (x) - y^{''} (x)

= x y^{''} (x) - y^{''} (x) + y^{'} (x)

\frac{4 t}{( t - 1 ) ^{2}}

\frac{3 x ^{2} + 8 x + 7}{( x + 1 ) ( x + 2 ) ^{2}}

- (\frac{9}{14} \cdot lo g_{2} (\frac{9}{14}) + \frac{5}{14} \cdot lo g_{2} (\frac{5}{14}))

\frac{2 x - 3 λ ( x - 1 ) ^{2}}{( 2 λ + 2 ) y}

\frac{1 + j}{2 ( 2 - 2 j )}

What is expand (x-1)y''(x)+y'(x) ?
The solution to expand (x-1)y''(x)+y'(x) is xy''(x)-y''(x)+y'(x)