What is expand e^{3x}(e^{-5x}+7) ?

The solution to expand e^{3x}(e^{-5x}+7) is e^{-2x}+7e^{3x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^{3x}(e^{-5x}+7)

expand

e^{3 x} (e^{- 5 x} + 7)

e^{- 2 x} + 7 e^{3 x}

Solution steps

e^{3 x} (e^{- 5 x} + 7)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{3 x}, b = e^{- 5 x}, c = 7

= e^{3 x} e^{- 5 x} + e^{3 x} \cdot 7

= e^{3 x} e^{- 5 x} + 7 e^{3 x}

e^{3 x} e^{- 5 x} = e^{- 2 x}

= e^{- 2 x} + 7 e^{3 x}

5 sec (\frac{π}{4} (x + 3))

\frac{( y + 2 ) ^{2}}{4}

(16 u - v = 1,) (- 8 u + 2 v = 16)

\frac{2 x + 4}{x ( x + 4 )}

\frac{( 12 + 10 x - 2 x ^{2} ) d x}{x ^{3} - 4 x}

What is expand e^{3x}(e^{-5x}+7) ?
The solution to expand e^{3x}(e^{-5x}+7) is e^{-2x}+7e^{3x}