What is expand (2x^2-3x+4)/(\sqrt[3]{x)} ?

The solution to expand (2x^2-3x+4)/(\sqrt[3]{x)} is (x^{2/3}(2x^2-3x+4))/x

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expand (2x^2-3x+4)/(\sqrt[3]{x)}

expand

\frac{x ^{\frac{2}{3}} ( 2 x ^{2} - 3 x + 4 )}{x}

Solution steps

Multiply by the conjugate

\frac{x ^{\frac{2}{3}}}{x ^{\frac{2}{3}}}

= \frac{x ^{\frac{2}{3}} ( 2 x ^{2} - 3 x + 4 )}{x}

5 cos (2) (\frac{3 π}{4} + x) + 2

\frac{x}{( x ^{2} - 4 ) ^{2}}

1 + (\frac{( 4 x ^{4} - 1 ) ^{2}}{16 x ^{4}})

\frac{1}{x ^{\frac{3}{2}} ( x + 4 a ) ^{\frac{3}{2}}}

\frac{k ( 5 + 3 t )}{1 + b t}

What is expand (2x^2-3x+4)/(\sqrt[3]{x)} ?
The solution to expand (2x^2-3x+4)/(\sqrt[3]{x)} is (x^{2/3}(2x^2-3x+4))/x