What is expand (100)/((2182j+1)(2182j+10)^2) ?

The solution to expand (100)/((2182j+1)(2182j+10)^2) is (25)/(2597193142j^3+24995901j^2+65460j+25)

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expand (100)/((2182j+1)(2182j+10)^2)

expand

\frac{100}{( 2182 j + 1 ) ( 2182 j + 10 ) ^{2}}

\frac{25}{2597193142 j ^{3} + 24995901 j ^{2} + 65460 j + 25}

Solution steps

\frac{100}{( 2182 j + 1 ) ( 2182 j + 10 ) ^{2}}

(2182 j + 10)^{2} = 4761124 j^{2} + 43640 j + 100

= \frac{100}{( 2182 j + 1 ) ( 4761124 j ^{2} + 43640 j + 100 )}

Factor

4761124 j^{2} + 43640 j + 100 : 4 (1190281 j^{2} + 10910 j + 25)

= \frac{100}{( 2182 j + 1 ) \cdot 4 ( 1190281 j ^{2} + 10910 j + 25 )}

Divide the numbers:

\frac{100}{4} = 25

= \frac{25}{( 2182 j + 1 ) ( 1190281 j ^{2} + 10910 j + 25 )}

Expand

(2182 j + 1) (1190281 j^{2} + 10910 j + 25) : 2597193142 j^{3} + 24995901 j^{2} + 65460 j + 25

= \frac{25}{2597193142 j ^{3} + 24995901 j ^{2} + 65460 j + 25}

\frac{6.3223 ( s + 1.4235 ) ^{2}}{s} + \frac{1}{s ( s + l ) ( s + 5 )}

(e^{t} cos (t) - e^{t} sin (t) + e^{t})^{2}

(2 - x) e^{x}

4 (1 + e^{2})

2 y d x + (x - sin (y^{\frac{1}{2}})) d y

What is expand (100)/((2182j+1)(2182j+10)^2) ?
The solution to expand (100)/((2182j+1)(2182j+10)^2) is (25)/(2597193142j^3+24995901j^2+65460j+25)