What is expand e^{2t}u(2-t) ?

The solution to expand e^{2t}u(2-t) is 2e^{2t}u-e^{2t}tu

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expand e^{2t}u(2-t)

expand

e^{2 t} u (2 - t)

2 e^{2 t} u - e^{2 t} t u

Solution steps

e^{2 t} u (2 - t)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 t} u, b = 2, c = t

= e^{2 t} u \cdot 2 - e^{2 t} u t

= 2 e^{2 t} u - e^{2 t} t u

\frac{( 2 x ^{3} + x + 1 ) d x}{( x ^{2} + 9 )}

\frac{( 6 x ^{2} - 4 x )}{( ( x + 2 ) ^{2} ( x - 1 ) )}

\frac{2 ^{^{'}} s + 3}{( s - 1 ) ^{3} ( s ^{3} + 1 )}

(x^{2} + 1)^{2} (2 x) d x

(- 8 t^{3} + 68 t^{2} - 204 t + 207) \cdot (- 1, + 2)

What is expand e^{2t}u(2-t) ?
The solution to expand e^{2t}u(2-t) is 2e^{2t}u-e^{2t}tu