What is expand (4x)/(ln(10)(x^2+1)) ?

The solution to expand (4x)/(ln(10)(x^2+1)) is (4x)/(ln(10)x^2+ln(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x)/(ln(10)(x^2+1))

expand

\frac{4 x}{ln ( 10 ) ( x ^{2} + 1 )}

\frac{4 x}{ln ( 10 ) x ^{2} + ln ( 10 )}

Solution steps

\frac{4 x}{ln ( 10 ) ( x ^{2} + 1 )}

Expand

ln (10) (x^{2} + 1) : ln (10) x^{2} + ln (10)

= \frac{4 x}{ln ( 10 ) x ^{2} + ln ( 10 )}

\frac{d}{d x} ((z) (4 z^{3} + 3 x z^{2} - x y z - 2 x y^{2} + 7))

\frac{3 x ^{2} + 2 x - 3}{( x ^{2} + 1 ) ^{2}}

\frac{1}{( z + 1 ) ( z - 1 )}

\frac{( x ^{2} + 5 x + 9 ) ^{n} + x ^{2} ( x + 5 ) ^{2} + 2}{x ^{2} + 5 x + 8}

What is expand (4x)/(ln(10)(x^2+1)) ?
The solution to expand (4x)/(ln(10)(x^2+1)) is (4x)/(ln(10)x^2+ln(10))