What is expand (3x^2(3x^2+2x^4))/8 ?

The solution to expand (3x^2(3x^2+2x^4))/8 is (3x^6)/4+(9x^4)/8

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expand (3x^2(3x^2+2x^4))/8

expand

\frac{3 x ^{2} ( 3 x ^{2} + 2 x ^{4} )}{8}

\frac{3 x ^{6}}{4} + \frac{9 x ^{4}}{8}

Solution steps

\frac{3 x ^{2} ( 3 x ^{2} + 2 x ^{4} )}{8}

Expand

3 x^{2} (3 x^{2} + 2 x^{4}) : 9 x^{4} + 6 x^{6}

= \frac{9 x ^{4} + 6 x ^{6}}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{4} + 6 x ^{6}}{8} = \frac{9 x ^{4}}{8} + \frac{6 x ^{6}}{8}

= \frac{9 x ^{4}}{8} + \frac{6 x ^{6}}{8}

Cancel

\frac{6 x ^{6}}{8} : \frac{3 x ^{6}}{4}

= \frac{9 x ^{4}}{8} + \frac{3 x ^{6}}{4}

Rewrite in standard form

= \frac{3 x ^{6}}{4} + \frac{9 x ^{4}}{8}

\frac{( s + 2 )}{( s ^{2} + 4 s + 3 ) \cdot ( s + 5 )}

\frac{4 s + 1}{5 ( s ^{2} + 2 s + 2 )}

- \frac{( 5 x ^{2} + 3 x - 17 )}{( x ^{2} - 7 ) ( x + 6 )}

\frac{\partial}{\partial x} ((z) (x + sin (x + z)))

\frac{1}{( ( s - 1 ) ( s ^{2} + 1 ) )}

What is expand (3x^2(3x^2+2x^4))/8 ?
The solution to expand (3x^2(3x^2+2x^4))/8 is (3x^6)/4+(9x^4)/8