What is expand f(2x-1)^5dx ?

The solution to expand f(2x-1)^5dx is 32fx^5dx-80fx^4dx+80fx^3dx-40fx^2dx+10fxdx-fdx

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expand f(2x-1)^5dx

expand

f (2 x - 1)^{5} d x

32 f x^{5} d x - 80 f x^{4} d x + 80 f x^{3} d x - 40 f x^{2} d x + 10 f x d x - fd x

Solution steps

f (2 x - 1)^{5} d x

(2 x - 1)^{5} = 32 x^{5} - 80 x^{4} + 80 x^{3} - 40 x^{2} + 10 x - 1

= f (32 x^{5} - 80 x^{4} + 80 x^{3} - 40 x^{2} + 10 x - 1) d x

Distribute parentheses

= fd x \cdot 32 x^{5} + fd x (- 80 x^{4}) + fd x \cdot 80 x^{3} + fd x (- 40 x^{2}) + fd x \cdot 10 x + fd x (- 1)

Apply minus-plus rules

+ (- a) = - a

= 32 f x^{5} d x - 80 f x^{4} d x + 80 f x^{3} d x - 40 f x^{2} d x + 10 f x d x - 1 \cdot fd x

Multiply:

1 \cdot f = f

= 32 f x^{5} d x - 80 f x^{4} d x + 80 f x^{3} d x - 40 f x^{2} d x + 10 f x d x - fd x

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\frac{1}{( s + 5 ) ( s ^{2} + 4 )}

- e^{- 0.01 (x + h)} - 0.18 (x + h) + 7

\frac{\partial}{\partial y} ((z) (x + 2 y + 3 z))

What is expand f(2x-1)^5dx ?
The solution to expand f(2x-1)^5dx is 32fx^5dx-80fx^4dx+80fx^3dx-40fx^2dx+10fxdx-fdx