What is expand e^t(\H(t)-\H(t-1)) ?

The solution to expand e^t(\H(t)-\H(t-1)) is e^t\H(t)-e^t\H(t-1)

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expand e^t(\H(t)-\H(t-1))

expand

e^{t} (H (t) - H (t - 1))

e^{t} H (t) - e^{t} H (t - 1)

Solution steps

e^{t} (H (t) - H (t - 1))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{t}, b = H (t), c = H (t - 1)

= e^{t} H (t) - e^{t} H (t - 1)

\frac{\partial}{\partial x} ((u) (3 x (x - 1)))

(5, 6, 8) - (7 i + 6 j)

2 x + y (cos (t)) + (2 y + x) e^{t}

\frac{3 ( 2 x - 1 ) ^{2}}{2 x}

\frac{3 x ^{2} - 6 x + 2}{2 ( 4 - 3 y ^{2} + 2 y ^{3} - 4 y )}

What is expand e^t(\H(t)-\H(t-1)) ?
The solution to expand e^t(\H(t)-\H(t-1)) is e^t\H(t)-e^t\H(t-1)