What is expand 2e^{x^2-4x}(2x-4) ?

The solution to expand 2e^{x^2-4x}(2x-4) is 4e^{x^2-4x}x-8e^{x^2-4x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2e^{x^2-4x}(2x-4)

expand

2 e^{x^{2} - 4 x} (2 x - 4)

4 e^{x^{2} - 4 x} x - 8 e^{x^{2} - 4 x}

Solution steps

2 e^{x^{2} - 4 x} (2 x - 4)

Apply the distributive law:

a (b - c) = ab - a c

a = 2 e^{x^{2} - 4 x}, b = 2 x, c = 4

= 2 e^{x^{2} - 4 x} \cdot 2 x - 2 e^{x^{2} - 4 x} \cdot 4

= 2 \cdot 2 e^{x^{2} - 4 x} x - 2 \cdot 4 e^{x^{2} - 4 x}

Simplify

2 \cdot 2 e^{x^{2} - 4 x} x - 2 \cdot 4 e^{x^{2} - 4 x} : 4 e^{x^{2} - 4 x} x - 8 e^{x^{2} - 4 x}

= 4 e^{x^{2} - 4 x} x - 8 e^{x^{2} - 4 x}

- (3 x + 8 - (- 15 + 6 x - (- 3 x + 2) - (5 x + 4) - 29) = - 5)

cos (2 (t - 2 π))

3 c - 3

\frac{2 ( x + 2 )}{5}

\frac{( x - 1 ) ^{4 n} ( x ^{3} + 8 ) ( x - 4 )}{x ^{2} - 2 x + 2}

What is expand 2e^{x^2-4x}(2x-4) ?
The solution to expand 2e^{x^2-4x}(2x-4) is 4e^{x^2-4x}x-8e^{x^2-4x}