What are the solutions to the equation -2x^2+x+10=0 ?

The solutions to the equation -2x^2+x+10=0 are x=-2,x= 5/2

Find the zeros of -2x^2+x+10=0

The zeros of -2x^2+x+10=0 are x=-2,x= 5/2

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- 2 x^{2} + x + 10 = 0

x = - 2, x = \frac{5}{2}

Solution steps

- 2 x^{2} + x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 10}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 10 = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 ( - 2 )}, x_{2} = \frac{- 1 - 9}{2 ( - 2 )}

x = \frac{- 1 + 9}{2 ( - 2 )} : - 2

x = \frac{- 1 - 9}{2 ( - 2 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = - 2, x = \frac{5}{2}

12 x^{2} - 61 x + 77

8 x^{2} - 3 x - 5

- 5 - \frac{x}{4} = \frac{x}{8} + 3

(\frac{3}{5} - \frac{1}{4} i) (\frac{2}{3} + \frac{2}{5} i)

1 - a^{8}

What are the solutions to the equation -2x^2+x+10=0 ?
The solutions to the equation -2x^2+x+10=0 are x=-2,x= 5/2
Find the zeros of -2x^2+x+10=0
The zeros of -2x^2+x+10=0 are x=-2,x= 5/2