What is expand (8x+1)/((x+1)^3(x^2+3)^2) ?

The solution to expand (8x+1)/((x+1)^3(x^2+3)^2) is (8x+1)/(x^7+3x^6+9x^5+19x^4+27x^3+33x^2+27x+9)

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expand (8x+1)/((x+1)^3(x^2+3)^2)

expand

\frac{8 x + 1}{( x + 1 ) ^{3} ( x ^{2} + 3 ) ^{2}}

\frac{8 x + 1}{x ^{7} + 3 x ^{6} + 9 x ^{5} + 19 x ^{4} + 27 x ^{3} + 33 x ^{2} + 27 x + 9}

Solution steps

\frac{8 x + 1}{( x + 1 ) ^{3} ( x ^{2} + 3 ) ^{2}}

(x + 1)^{3} = x^{3} + 3 x^{2} + 3 x + 1

= \frac{8 x + 1}{( x ^{3} + 3 x ^{2} + 3 x + 1 ) ( x ^{2} + 3 ) ^{2}}

(x^{2} + 3)^{2} = x^{4} + 6 x^{2} + 9

= \frac{8 x + 1}{( x ^{3} + 3 x ^{2} + 3 x + 1 ) ( x ^{4} + 6 x ^{2} + 9 )}

Expand

(x^{3} + 3 x^{2} + 3 x + 1) (x^{4} + 6 x^{2} + 9) : x^{7} + 3 x^{6} + 9 x^{5} + 19 x^{4} + 27 x^{3} + 33 x^{2} + 27 x + 9

= \frac{8 x + 1}{x ^{7} + 3 x ^{6} + 9 x ^{5} + 19 x ^{4} + 27 x ^{3} + 33 x ^{2} + 27 x + 9}

\frac{2 7 ^{x} + 9 ^{x} - 20 \cdot 3 ^{x}}{3 ^{x} ( 3 ^{x} - 4 )}

\frac{( b ^{2} + ab + b c + a c ) ( a + c )}{3 ab c}

\frac{x ^{2} - 4}{( x - 1 ) ^{2}}

\frac{( a ^{2} + 4 ) ^{2}}{4 a}

A (2, 4) B (- 8, - 12)

What is expand (8x+1)/((x+1)^3(x^2+3)^2) ?
The solution to expand (8x+1)/((x+1)^3(x^2+3)^2) is (8x+1)/(x^7+3x^6+9x^5+19x^4+27x^3+33x^2+27x+9)