What is expand 2(pi/6-(sqrt(3))/4) ?

The solution to expand 2(pi/6-(sqrt(3))/4) is pi/3-(sqrt(3))/2

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expand 2(pi/6-(sqrt(3))/4)

expand

2 (\frac{π}{6} - \frac{3}{4})

\frac{π}{3} - \frac{3}{2}

Solution steps

2 (\frac{π}{6} - \frac{3}{4})

Apply the distributive law:

a (b - c) = ab - a c

a = 2, b = \frac{π}{6}, c = \frac{3}{4}

= 2 \cdot \frac{π}{6} - 2 \cdot \frac{3}{4}

Simplify

2 \cdot \frac{π}{6} - 2 \cdot \frac{3}{4} : \frac{π}{3} - \frac{3}{2}

= \frac{π}{3} - \frac{3}{2}

d x ((x - sin (x)) (x + cos (x)))

10 (k x)

e [3414 - 316 (ln (60)) - 316 (ln (60))^{2}]

x^{2} y^{'} (x) + (x + 1) y

\frac{1 - p + 3}{( p + 2 ) ^{2}}

What is expand 2(pi/6-(sqrt(3))/4) ?
The solution to expand 2(pi/6-(sqrt(3))/4) is pi/3-(sqrt(3))/2