What is expand cosh(t+pi)u(t+pi) ?

The solution to expand cosh(t+pi)u(t+pi) is tucosh(t+pi)+piucosh(t+pi)

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expand cosh(t+pi)u(t+pi)

expand

cosh (t + π) u (t + π)

t u cosh (t + π) + π u cosh (t + π)

Solution steps

cosh (t + π) u (t + π)

= u cosh (t + π) (t + π)

Apply the distributive law:

a (b + c) = ab + a c

a = cosh (t + π) u, b = t, c = π

= cosh (t + π) u t + cosh (t + π) u π

= t u cosh (t + π) + π u cosh (t + π)

\frac{( x + 12 ) ( x - 3 )}{( x + 12 ) 5 x}

[\frac{1}{( x + 1 ) ^{2}}]^{^{'}}

ln (16) x^{2}

(3 e^{3 x} + 4 e^{- 4 x})^{3}

\frac{a ( b - c )}{d}

What is expand cosh(t+pi)u(t+pi) ?
The solution to expand cosh(t+pi)u(t+pi) is tucosh(t+pi)+piucosh(t+pi)