What is expand (e^{jθ}+e^{-jθ})^2 ?

The solution to expand (e^{jθ}+e^{-jθ})^2 is e^{2jθ}+2+e^{-2jθ}

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expand (e^{jθ}+e^{-jθ})^2

expand

(e^{j θ} + e^{- j θ})^{2}

e^{2 j θ} + 2 + e^{- 2 j θ}

Solution steps

(e^{j θ} + e^{- j θ})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = e^{j θ}, b = e^{- j θ}

= (e^{j θ})^{2} + 2 e^{j θ} e^{- j θ} + (e^{- j θ})^{2}

Simplify

(e^{j θ})^{2} + 2 e^{j θ} e^{- j θ} + (e^{- j θ})^{2} : e^{2 j θ} + 2 + e^{- 2 j θ}

= e^{2 j θ} + 2 + e^{- 2 j θ}

(z - e^{\frac{π}{4}}) (z - e^{- \frac{π}{4}})

- \frac{7 x + 15}{( x - 1 ) ^{2}}

A (A + B^{^{'}} C) + A (B^{^{'}} + C)

(2 e^{x} - 1)^{2}

(n + 1)^{2}!

What is expand (e^{jθ}+e^{-jθ})^2 ?
The solution to expand (e^{jθ}+e^{-jθ})^2 is e^{2jθ}+2+e^{-2jθ}