What is expand 4(x+Δx)^3 ?

The solution to expand 4(x+Δx)^3 is 4x^3+12Δx^3+12Δ^2x^3+4Δ^3x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 4(x+Δx)^3

expand

4 (x + Δ x)^{3}

4 x^{3} + 12Δ x^{3} + 12 Δ^{2} x^{3} + 4 Δ^{3} x^{3}

Solution steps

4 (x + Δ x)^{3}

(x + Δ x)^{3} = x^{3} + 3Δ x^{3} + 3 Δ^{2} x^{3} + Δ^{3} x^{3}

= 4 (x^{3} + 3Δ x^{3} + 3 Δ^{2} x^{3} + Δ^{3} x^{3})

Distribute parentheses

= 4 x^{3} + 4 \cdot 3Δ x^{3} + 4 \cdot 3 Δ^{2} x^{3} + 4 Δ^{3} x^{3}

Multiply the numbers:

4 \cdot 3 = 12

= 4 x^{3} + 12Δ x^{3} + 12 Δ^{2} x^{3} + 4 Δ^{3} x^{3}

\frac{( t + 1 )}{( ( 2 t + 1 ) ^{\frac{( 3 )}{( 2 )}} )}

(x^{3} - 5 x^{2}) ln (x^{3} + 6 x^{2} + 5 x)

\frac{x ^{2} + 4 x + 4}{( x + 5 ) ( x - 2 )}

\frac{2 ( 54 - 4 2 )}{9}

What is expand 4(x+Δx)^3 ?
The solution to expand 4(x+Δx)^3 is 4x^3+12Δx^3+12Δ^2x^3+4Δ^3x^3