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Popular >

expand f'(2)(x-y=1)

Solution

expand

f^{'} (2) (x - y = 1)

Solution

x f' (2) - y f' (2) = 1

Solution steps

f^{'} (2) (x - y = 1)

= f^{^{'}} (2) (x - 1 y =)

Apply the distributive law:

a (b - c) = ab - a c

a = f^{'} (2), b = x, c = y = 1

f^{^{'}} (2) x - f^{^{'}} (2) y = 1

x f^{^{'}} (2) - y f^{^{'}} (2) = 1

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Frequently Asked Questions (FAQ)

What is expand f'(2)(x-y=1) ?
The solution to expand f'(2)(x-y=1) is xf'(2)-yf'(2)=1