What is expand (x)(((96-16x))/(12))^2 ?

The solution to expand (x)(((96-16x))/(12))^2 is (16x^3)/9-(64x^2)/3+64x

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expand (x)(((96-16x))/(12))^2

expand

(x) (\frac{( 96 - 16 x )}{12})^{2}

\frac{16 x ^{3}}{9} - \frac{64 x ^{2}}{3} + 64 x

Solution steps

(x) (\frac{96 - 16 x}{12})^{2}

Remove parentheses:

(a) = a

= x (\frac{96 - 16 x}{12})^{2}

(\frac{96 - 16 x}{12})^{2} = \frac{16 x ^{2} - 192 x + 576}{3 ^{2}}

= \frac{16 x ^{2} - 192 x + 576}{3 ^{2}} x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 16 x ^{2} - 192 x + 576 ) x}{3 ^{2}}

3^{2} = 9

= \frac{x ( 16 x ^{2} - 192 x + 576 )}{9}

Expand

(16 x^{2} - 192 x + 576) x : 16 x^{3} - 192 x^{2} + 576 x

= \frac{16 x ^{3} - 192 x ^{2} + 576 x}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{3} - 192 x ^{2} + 576 x}{9} = \frac{16 x ^{3}}{9} - \frac{192 x ^{2}}{9} + \frac{576 x}{9}

= \frac{16 x ^{3}}{9} - \frac{192 x ^{2}}{9} + \frac{576 x}{9}

Cancel

\frac{192 x ^{2}}{9} : \frac{64 x ^{2}}{3}

= \frac{16 x ^{3}}{9} - \frac{64 x ^{2}}{3} + \frac{576 x}{9}

Divide the numbers:

\frac{576}{9} = 64

= \frac{16 x ^{3}}{9} - \frac{64 x ^{2}}{3} + 64 x

- 2 (e^{x} + e^{x} x)

\frac{( x + 3 ) ^{4}}{4}

\frac{3 x + 5}{( x + 2 ) ^{2} ( x ^{2} + 2 )}

10 x (2 - ln (x))

\frac{5 ( 9 - 201 )}{3}

What is expand (x)(((96-16x))/(12))^2 ?
The solution to expand (x)(((96-16x))/(12))^2 is (16x^3)/9-(64x^2)/3+64x