What are the solutions to the equation x^2+10x=2x ?

The solutions to the equation x^2+10x=2x are x=0,x=-8

Find the zeros of x^2+10x=2x

The zeros of x^2+10x=2x are x=0,x=-8

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x^{2} + 10 x = 2 x

x = 0, x = - 8

Solution steps

x^{2} + 10 x = 2 x

Move

2 x

to the left side

x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 1}, x_{2} = \frac{- 8 - 8}{2 \cdot 1}

x = \frac{- 8 + 8}{2 \cdot 1} : 0

x = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

\frac{f}{- 7} - 8 = 2

\frac{4}{3 + 6}

2 lo g_{2} (8)

2 x^{2} - 4 x - 8 = 0

\frac{64}{- 8}

What are the solutions to the equation x^2+10x=2x ?
The solutions to the equation x^2+10x=2x are x=0,x=-8
Find the zeros of x^2+10x=2x
The zeros of x^2+10x=2x are x=0,x=-8