What is expand 10(-2e^{-2x}+3e^{-3x}) ?

The solution to expand 10(-2e^{-2x}+3e^{-3x}) is -20e^{-2x}+30e^{-3x}

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expand 10(-2e^{-2x}+3e^{-3x})

expand

10 (- 2 e^{- 2 x} + 3 e^{- 3 x})

- 20 e^{- 2 x} + 30 e^{- 3 x}

Solution steps

10 (- 2 e^{- 2 x} + 3 e^{- 3 x})

Apply the distributive law:

a (b + c) = ab + a c

a = 10, b = - 2 e^{- 2 x}, c = 3 e^{- 3 x}

= 10 (- 2 e^{- 2 x}) + 10 \cdot 3 e^{- 3 x}

Apply minus-plus rules

+ (- a) = - a

= - 10 \cdot 2 e^{- 2 x} + 10 \cdot 3 e^{- 3 x}

Simplify

- 10 \cdot 2 e^{- 2 x} + 10 \cdot 3 e^{- 3 x} : - 20 e^{- 2 x} + 30 e^{- 3 x}

= - 20 e^{- 2 x} + 30 e^{- 3 x}

\frac{x ^{2} + 7 x + 11}{( x + 2 ) ( x + 1 ) ( x + 3 )}

e^{(x^{2} + y^{2})^{2}}

(x^{2} - 1) e^{\frac{1}{x - 3}}

- \frac{e ^{x}}{( c + e ^{x} ) ^{2}}

, (5 x - 8 q^{2}) (2 (m - 2))

What is expand 10(-2e^{-2x}+3e^{-3x}) ?
The solution to expand 10(-2e^{-2x}+3e^{-3x}) is -20e^{-2x}+30e^{-3x}