What is expand (4x^2-8x+1)/((x+2)(x^2-2x+3)) ?

The solution to expand (4x^2-8x+1)/((x+2)(x^2-2x+3)) is (4x^2-8x+1)/(x^3-x+6)

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expand (4x^2-8x+1)/((x+2)(x^2-2x+3))

expand

\frac{4 x ^{2} - 8 x + 1}{( x + 2 ) ( x ^{2} - 2 x + 3 )}

\frac{4 x ^{2} - 8 x + 1}{x ^{3} - x + 6}

Solution steps

\frac{4 x ^{2} - 8 x + 1}{( x + 2 ) ( x ^{2} - 2 x + 3 )}

Expand

(x + 2) (x^{2} - 2 x + 3) : x^{3} - x + 6

= \frac{4 x ^{2} - 8 x + 1}{x ^{3} - x + 6}

π (2 ln (3) + \frac{2}{3})

\frac{- 4 x ^{2} - 10 x - 4}{( x ^{2} - 1 ) ^{2}}

(- 2, 2) y (3, - 5)

\frac{( x + 1 ) ^{2}}{1 + x ^{2}}

(e^{x} + ln (y) + \frac{y}{x}) d x + (\frac{x}{y} + ln (x) + sin (x)) d y

What is expand (4x^2-8x+1)/((x+2)(x^2-2x+3)) ?
The solution to expand (4x^2-8x+1)/((x+2)(x^2-2x+3)) is (4x^2-8x+1)/(x^3-x+6)