What is expand 1/((x^2+1)(x+2)) ?

The solution to expand 1/((x^2+1)(x+2)) is 1/(x^3+2x^2+x+2)

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expand 1/((x^2+1)(x+2))

expand

\frac{1}{( x ^{2} + 1 ) ( x + 2 )}

\frac{1}{x ^{3} + 2 x ^{2} + x + 2}

Solution steps

\frac{1}{( x ^{2} + 1 ) ( x + 2 )}

Expand

(x^{2} + 1) (x + 2) : x^{3} + 2 x^{2} + x + 2

= \frac{1}{x ^{3} + 2 x ^{2} + x + 2}

[\frac{2 s ^{3} + 3 s ^{2} + 2 s + 27}{( s ^{2} + 9 ) ( s ^{2} + 1 )}]

x e^{6 x y} (y e^{6 x y} + x)

\frac{1 - x}{( 2 - x ) ^{2}}

\frac{x ^{2} ( 9 - x ^{2} )}{( 3 - x ^{2} ) ^{2}}

a cos (ω t - k x) + a cos (ω t - k (x + δ x))

What is expand 1/((x^2+1)(x+2)) ?
The solution to expand 1/((x^2+1)(x+2)) is 1/(x^3+2x^2+x+2)