What is expand \H(x-2)(t-2)^2 ?

The solution to expand \H(x-2)(t-2)^2 is t^2\H(x-2)-4t\H(x-2)+4\H(x-2)

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expand \H(x-2)(t-2)^2

expand

H (x - 2) (t - 2)^{2}

t^{2} H (x - 2) - 4 t H (x - 2) + 4 H (x - 2)

Solution steps

H (x - 2) (t - 2)^{2}

(t - 2)^{2} = t^{2} - 4 t + 4

= H (x - 2) (t^{2} - 4 t + 4)

Distribute parentheses

= H (x - 2) t^{2} + H (x - 2) (- 4 t) + H (x - 2) \cdot 4

Apply minus-plus rules

+ (- a) = - a

= t^{2} H (x - 2) - 4 t H (x - 2) + 4 H (x - 2)

\frac{4 e ^{- s} - 2 s e ^{- s} - s ^{2} + s}{s ( s - 1 )}

(1 - cos (θ))^{2} + sin^{2} (θ)

(4 x - 1) ln (2)

\frac{( 1 - t ) b \cdot d}{b ( 1 - t ) + c}

\frac{1}{k ( a - x ) ( b - x )}

What is expand \H(x-2)(t-2)^2 ?
The solution to expand \H(x-2)(t-2)^2 is t^2\H(x-2)-4t\H(x-2)+4\H(x-2)