What is (\partial)/(\partial t)((x)(2s-t)) ?

The answer to (\partial)/(\partial t)((x)(2s-t)) is -x

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(\partial)/(\partial t)((x)(2s-t))

\frac{\partial}{\partial t} ((x) (2 s - t))

- x

Solution steps

\frac{\partial}{\partial t} ((x) (2 s - t))

Treat

x, s

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial t} (2 s - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{\partial}{\partial t} (2 s) - \frac{\partial}{\partial t} (t))

\frac{\partial}{\partial t} (2 s) = 0

\frac{\partial}{\partial t} (t) = 1

= x (0 - 1)

Simplify

= - x

\frac{2 x}{( x + 1 ) ^{3}}

(x + 2) ln (5)

\frac{2 ( x ) ^{4} - x ^{3} - x + 1}{( 1 - x ) ^{2}}

\frac{( 2 s - 5 )}{( s - 3 ) ( s - 1 )}

\frac{1}{x ( a - x )}

What is (\partial)/(\partial t)((x)(2s-t)) ?
The answer to (\partial)/(\partial t)((x)(2s-t)) is -x