What is the f(x)=(2x^5+28x^3-6x)/((x^2-1)^4) ?

The f(x)=(2x^5+28x^3-6x)/((x^2-1)^4) is

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f(x)=(2x^5+28x^3-6x)/((x^2-1)^4)

f (x) = \frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}}

Domain : x < - 1 or - 1 < x < 1 or x > 1

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), (- 7 + 213, 0), (- - 7 + 213, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - 1, x = 1, Horizontal y = 0

Extreme Points : Maximum - \frac{5.20194 E 15}{5.0 E 16}, \frac{6.25 E 1 5 ^{4} ( - 2 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{5}{2}} - 28 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{3}{2}} + 6 \frac{5.20194 E 15}{5.0 E 16} )}{5.59976 E 1 5 ^{4}}, Minimum \frac{5.20194 E 15}{5.0 E 16}, \frac{6.25 E 1 5 ^{4} ( 2 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{5}{2}} + 28 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{3}{2}} - 6 \frac{5.20194 E 15}{5.0 E 16} )}{5.59976 E 1 5 ^{4}}

Solution steps

Domain of

\frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}} : x < - 1 or - 1 < x < 1 or x > 1

Range of

\frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}} : - \infty < f (x) < \infty

Axis interception points of

\frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}} :

X Intercepts

: (0, 0), (- 7 + 213, 0), (- - 7 + 213, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}} :

Vertical

: x = - 1, x = 1,

Horizontal

: y = 0

Extreme Points of

\frac{2 x ^{5} + 28 x ^{3} - 6 x}{( x ^{2} - 1 ) ^{4}} :

Maximum

- \frac{5.20194 E 15}{5.0 E 16}, \frac{6.25 E 1 5 ^{4} ( - 2 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{5}{2}} - 28 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{3}{2}} + 6 \frac{5.20194 E 15}{5.0 E 16} )}{5.59976 E 1 5 ^{4}},

Minimum

\frac{5.20194 E 15}{5.0 E 16}, \frac{6.25 E 1 5 ^{4} ( 2 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{5}{2}} + 28 ( \frac{5.20194 E 15}{5.0 E 16} ) ^{\frac{3}{2}} - 6 \frac{5.20194 E 15}{5.0 E 16} )}{5.59976 E 1 5 ^{4}}

\frac{100 a ^{2} - 20 a + 1}{100}

(y^{'} (x) + (1 - sec (x)) y^{2}) tan (x)

- \frac{2 ( - x + 1 )}{x ^{3}}

(e^{\frac{jω}{2}} - e^{- \frac{jω}{2}})^{2}

cos (x^{2} + 3 y - 1) (2 x + 3 \frac{d y}{d x})

What is the f(x)=(2x^5+28x^3-6x)/((x^2-1)^4) ?
The f(x)=(2x^5+28x^3-6x)/((x^2-1)^4) is