What is expand (3x^2-7x-12)/((x+4)(x-4)^2) ?

The solution to expand (3x^2-7x-12)/((x+4)(x-4)^2) is (3x^2-7x-12)/(x^3-4x^2-16x+64)

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expand (3x^2-7x-12)/((x+4)(x-4)^2)

expand

\frac{3 x ^{2} - 7 x - 12}{( x + 4 ) ( x - 4 ) ^{2}}

\frac{3 x ^{2} - 7 x - 12}{x ^{3} - 4 x ^{2} - 16 x + 64}

Solution steps

\frac{3 x ^{2} - 7 x - 12}{( x + 4 ) ( x - 4 ) ^{2}}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{3 x ^{2} - 7 x - 12}{( x + 4 ) ( x ^{2} - 8 x + 16 )}

Expand

(x + 4) (x^{2} - 8 x + 16) : x^{3} - 4 x^{2} - 16 x + 64

= \frac{3 x ^{2} - 7 x - 12}{x ^{3} - 4 x ^{2} - 16 x + 64}

3 sin (2 (π - θ))

\frac{( e ^{- s} )}{s ( s + 1 )}

\frac{1}{( x - 2 ) ( x + 2 )}

(\frac{s ^{2} + s + 1}{s ( s + 1 )}) + 1

\frac{( x - 1 ) y ^{4}}{( x - 1 ) ^{2} + y ^{8}}

What is expand (3x^2-7x-12)/((x+4)(x-4)^2) ?
The solution to expand (3x^2-7x-12)/((x+4)(x-4)^2) is (3x^2-7x-12)/(x^3-4x^2-16x+64)