What are the solutions to the equation 5(x+1)^2=60 ?

The solutions to the equation 5(x+1)^2=60 are x=2sqrt(3)-1,x=-2sqrt(3)-1

Find the zeros of 5(x+1)^2=60

The zeros of 5(x+1)^2=60 are x=2sqrt(3)-1,x=-2sqrt(3)-1

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5 (x + 1)^{2} = 60

x = 23 - 1, x = - 23 - 1

Decimal Notation

x = 2.46410 \dots, x = - 4.46410 \dots

Solution steps

5 (x + 1)^{2} = 60

Divide both sides by

5

(x + 1)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 12 : x = 23 - 1

Solve

x + 1 = - 12 : x = - 23 - 1

The solutions to the quadratic equation are:

x = 23 - 1, x = - 23 - 1

9 - x = 4

7 + 9

0 \geq 2 x^{2} - 4 x + 1

\frac{x ^{- \frac{1}{3}}}{x ^{\frac{2}{3}}}

\frac{20 !}{4 ! 16 !}

What are the solutions to the equation 5(x+1)^2=60 ?
The solutions to the equation 5(x+1)^2=60 are x=2sqrt(3)-1,x=-2sqrt(3)-1
Find the zeros of 5(x+1)^2=60
The zeros of 5(x+1)^2=60 are x=2sqrt(3)-1,x=-2sqrt(3)-1