What is expand f(-8sec(x)tan(x)+9sec^2(x))dx ?

The solution to expand f(-8sec(x)tan(x)+9sec^2(x))dx is -8fsec(x)tan(x)dx+9fsec^2(x)dx

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expand f(-8sec(x)tan(x)+9sec^2(x))dx

expand

f (- 8 sec (x) tan (x) + 9 sec^{2} (x)) d x

- 8 f sec (x) tan (x) d x + 9 f sec^{2} (x) d x

Solution steps

f (- 8 sec (x) tan (x) + 9 sec^{2} (x)) d x

Apply the distributive law:

a (b + c) = ab + a c

a = fd x, b = - 8 sec (x) tan (x), c = 9 sec^{2} (x)

= fd x (- 8 sec (x) tan (x)) + fd x \cdot 9 sec^{2} (x)

Apply minus-plus rules

+ (- a) = - a

= - 8 f sec (x) tan (x) d x + 9 f sec^{2} (x) d x

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What is expand f(-8sec(x)tan(x)+9sec^2(x))dx ?
The solution to expand f(-8sec(x)tan(x)+9sec^2(x))dx is -8fsec(x)tan(x)dx+9fsec^2(x)dx