What is expand 5((4,0,-8)-8(6,-1,-4)) ?

The solution to expand 5((4,0,-8)-8(6,-1,-4)) is 5*4*0,,-5*8-5*8*6,5*8*1,5*8*4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 5((4,0,-8)-8(6,-1,-4))

expand

5 ((4, 0, - 8) - 8 (6, - 1, - 4))

5 \cdot 4 \cdot 0,, - 5 \cdot 8 - 5 \cdot 8 \cdot 6, 5 \cdot 8 \cdot 1, 5 \cdot 8 \cdot 4

Solution steps

5 ((4, 0, - 8) - 8 (6, - 1, - 4))

= 5 ((4 \cdot 0,, - 8) - 8 (6, - 1, - 4))

Expand

5 ((4, 0, - 8) - 8 (6, - 1, - 4)) : 5 (4 \cdot 0,, - 8) - 5 \cdot 8 (6, - 1, - 4)

= 5 (4 \cdot 0,, - 8) - 5 \cdot 8 (6, - 1, - 4)

Expand

5 (4 \cdot 0,, - 8) : 5 \cdot 4 \cdot 0,, - 5 \cdot 8

= 5 \cdot 4 \cdot 0,, - 5 \cdot 8 - 5 \cdot 8 (6, - 1, - 4)

Expand

- 5 \cdot 8 (6, - 1, - 4) : - 5 \cdot 8 \cdot 6, 5 \cdot 8 \cdot 1, 5 \cdot 8 \cdot 4

= 5 \cdot 4 \cdot 0,, - 5 \cdot 8 - 5 \cdot 8 \cdot 6, 5 \cdot 8 \cdot 1, 5 \cdot 8 \cdot 4

\frac{5 ( 3 + 3 )}{3}

- 3 (27 π^{3} - 1)

\frac{16}{( s ^{2} + 4 ) ^{2}}

(x^{2} + 2 x + 3)^{7}

(a + b x + cy + d x^{2} + e y^{2} + f x y)^{2}

What is expand 5((4,0,-8)-8(6,-1,-4)) ?
The solution to expand 5((4,0,-8)-8(6,-1,-4)) is 5*4*0,,-5*8-5*8*6,5*8*1,5*8*4