What is expand (n(4n^2+6n+3))/(4(n+1)^2) ?

The solution to expand (n(4n^2+6n+3))/(4(n+1)^2) is (4n^3+6n^2+3n)/(4n^2+8n+4)

Popular >

expand (n(4n^2+6n+3))/(4(n+1)^2)

expand

\frac{n ( 4 n ^{2} + 6 n + 3 )}{4 ( n + 1 ) ^{2}}

\frac{4 n ^{3} + 6 n ^{2} + 3 n}{4 n ^{2} + 8 n + 4}

Solution steps

\frac{n ( 4 n ^{2} + 6 n + 3 )}{4 ( n + 1 ) ^{2}}

(n + 1)^{2} = n^{2} + 2 n + 1

= \frac{n ( 4 n ^{2} + 6 n + 3 )}{4 ( n ^{2} + 2 n + 1 )}

Expand

4 (n^{2} + 2 n + 1) : 4 n^{2} + 8 n + 4

= \frac{n ( 4 n ^{2} + 6 n + 3 )}{4 n ^{2} + 8 n + 4}

Expand

n (4 n^{2} + 6 n + 3) : 4 n^{3} + 6 n^{2} + 3 n

= \frac{4 n ^{3} + 6 n ^{2} + 3 n}{4 n ^{2} + 8 n + 4}

\frac{2 ( x ) ^{3} + ( x ) - 1}{( ( x ) + 1 ) ( ( x ) + 2 ) ( ( x ) - 2 )}

\frac{\partial}{\partial x} ((z) (x^{4} - 4 x y + 9 y^{3}))

\frac{1}{( x + 1 ) \cdot ( x ^{3} - 1 )}

x (54 - 4 ln (x))

What is expand (n(4n^2+6n+3))/(4(n+1)^2) ?
The solution to expand (n(4n^2+6n+3))/(4(n+1)^2) is (4n^3+6n^2+3n)/(4n^2+8n+4)