What is expand ln(z)(z-3)^2 ?

The solution to expand ln(z)(z-3)^2 is z^2ln(z)-6zln(z)+9ln(z)

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expand ln(z)(z-3)^2

expand

ln (z) (z - 3)^{2}

z^{2} ln (z) - 6 z ln (z) + 9 ln (z)

Solution steps

ln (z) (z - 3)^{2}

(z - 3)^{2} = z^{2} - 6 z + 9

= ln (z) (z^{2} - 6 z + 9)

Distribute parentheses

= ln (z) z^{2} + ln (z) (- 6 z) + ln (z) \cdot 9

Apply minus-plus rules

+ (- a) = - a

= z^{2} ln (z) - 6 z ln (z) + 9 ln (z)

\frac{( 1 + x ^{2} - x ^{3} ) ( 1 - x ^{2} + x ^{3} )}{1 - x ^{2} - x ^{3}}

\frac{8}{( x ^{2} + 4 ) ( x ^{2} + 6 x + 25 )}

\frac{1}{4} ((s + 2)^{2} (s - 2)^{3} (s^{2} + 4))

10 - 10 e^{- 3 x} (cos (3 x) + sin (3 x))

(- 4) \cdot 8 a + 16

What is expand ln(z)(z-3)^2 ?
The solution to expand ln(z)(z-3)^2 is z^2ln(z)-6zln(z)+9ln(z)