What is expand (λ-e^{-w}μ)(e^w-1) ?

The solution to expand (λ-e^{-w}μ)(e^w-1) is λe^w-λ-μ+e^{-w}μ

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expand (λ-e^{-w}μ)(e^w-1)

expand

(λ - e^{- w} μ) (e^{w} - 1)

λ e^{w} - λ - μ + e^{- w} μ

Solution steps

(λ - e^{- w} μ) (e^{w} - 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = λ, b = - e^{- w} μ, c = e^{w}, d = - 1

= λ e^{w} + λ (- 1) + (- e^{- w} μ) e^{w} + (- e^{- w} μ) (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= λ e^{w} - 1 \cdot λ - e^{w} e^{- w} μ + 1 \cdot e^{- w} μ

Simplify

λ e^{w} - 1 \cdot λ - e^{w} e^{- w} μ + 1 \cdot e^{- w} μ : λ e^{w} - λ - μ + e^{- w} μ

= λ e^{w} - λ - μ + e^{- w} μ

\frac{x - 4}{( x + 1 ) ( x + 2 )}

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p or (- 5, - 2)

\frac{y ( x + y )}{x ^{2}}

0.8 \cdot sin (0.628 \cdot (x - 2.4))

What is expand (λ-e^{-w}μ)(e^w-1) ?
The solution to expand (λ-e^{-w}μ)(e^w-1) is λe^w-λ-μ+e^{-w}μ